Select *
is not valid.- Customer_Table
- Cust_Name
- Cust_Address
- Cust_City
- Cust_State
- Cust_Zip
To retrieve all the rows from the database, you might construct a query similar to the following:
SELECT Cust_Name, Cust_Address, Cust_City, Cust_State, Cust_Zip from Customer_Table;
You will rarely want to match your transaction against all the rows in the database. To return only relevant candidate records, add a WHERE clause using variable substitution. Variable substitution refers to a special notation that you will use to cause the Candidate Selection engine to replace the variable with the actual data from your suspect record.
To use variable substitution, enclose the field name in braces preceded by a dollar sign using the form ${FieldName}
. For example, the following query will return only those records that have a value in Cust_Zip that matches the value in PostalCode on the suspect record.
SELECT Cust_Name, Cust_Address, Cust_City, Cust_State,Cust_Zip
FROM Customer_Table
WHERE Cust_Zip = ${PostalCode};
For SQL 2000, the data type needs to be identical to the data type for Candidate Finder. The JDBC driver sets the Candidate Finder input variable (Ex: ${MatchKey}) that is used in the WHERE clause to a data type of nVarChar(4000). If the data in the database is set to a data type of VarChar, SQL Server will ignore the index on the database. If the index is ignored, then performance will be degraded. Therefore, use the following query for SQL 2000:
SELECT Cust_Name, Cust_Address, Cust_City, Cust_State,Cust_Zip
FROM Customer_Table
WHERE Cust_Zip = CAST(${PostalCode} AS VARCHAR(255));